6. Composition of matter class 8 question answer maharshtra board

Class 8 general science chapter 6 question answer – Class 8 question answer Compound of matter – Compound of matter class 8 question answer maharshtra
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Class 8 Composition of matter exercise question answer general science


Class 8 general science chapter 6 question answer – Class 8 question answer Compound of matter – Compound of matter class 8 question answer maharshtra board


1. Choose the appropriate option and rewrite the following statements.


a. The intermolecular force is …….. in the particles of solid.

 

i. minimum

ii. moderate

iii. maximum

iv. Indefinite

Ans: The intermolecular force is maximum  in the particles of solid.


b. Solids retain their volume even when external pressure is applied. This property is called …….. .

 

i. plasticity

ii. incompressibility

iii. fluidity

iv. Elasticity

Ans: Solids retain their volume even when external pressure is applied. This property is called Elasticity.


Class 8 general science chapter 6 question answer – Class 8 question answer Compound of matter – Compound of matter class 8 question answer maharshtra board


C. Matter is classified into the types mixture, compound and element, by applying the  criterion …….. .

 

i. states of matter

ii. phases of matters

iii. chemical composition of matter 

iv. all of these

Ans: Matter is classified into the types mixture, compound and element, by applying the  criterion chemical composition of matter  .



d. Matter that contain two or more constituent substances is called …….. .


i. mixture

ii. compound

iii. element

iv. Metalloid

Ans: Matter that contain two or more constituent substances is called mixture .



e. Milk is an example of type of matter called …….. .

i. solution

ii. homogeneous mixture

iii. heterogeneous mixture

iv. suspension

Ans: Milk is an example of type of matter called heterogeneous mixture .


f. Water, mercury and bromine are similar to each other, because three are …….. .

i. liquids

ii. compounds

iii. nonmetals

iv. elements

Ans: Water, mercury and bromine are similar to each other, because three are liquids.



g. Valency of carbon is 4 and that of oxygen is 2. From this, we understand that there  are ……  chemical bond/bonds between  the carbon atom and one oxygen atom in the compound-carbon dioxide.

 

i. 1

ii. 2

iii. 3

iv. 4

Ans: Valency of carbon is 4 and that of oxygen is 2. From this, we understand that there  are 2 chemical bond/bonds between  the carbon atom and one oxygen atom in the compound-carbon dioxide.


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2. Identify the odd term out and explain.


Gold, silver, copper, brass

Ans: brass (Other are Element)

 

Hydrogen, hydrogen peroxide, carbon dioxide, water vapour.

Ans: Hydrogen (Other are compounds)

 

Milk, lemon juice, carbon, steel.

Ans: Carbon (other are mixtures)

 

Water, mercury, bromine, petrol.

Ans: Petrol ( other are inorganic compounds)

 

Sugar, salt, baking soda, blue vitriol.

Ans: Sugar (Other are inorganic compound)

 

Hydrogen, sodium, potassium, carbon.

Ans: Carbon ( Other are monovalent elements)

 

3. Answer the following question.


a. Plants synthesize glucose in sunlight with the help of chlorophyll from carbon  dioxide and water and give away oxygen. Identify the four compounds in this process and name their types.

Ans:

Photosynthesis:

Carbon dioxide, water, glucose, and chlorophyll are compounds.

Types: Organic compounds : Glucose

Inorganic compounds: Carbon dioxide and water

Complex compounds: Chlorophyll.

 


b. In one sample of brass, the following ingredients were found : copper (70%) and zinc (30%). Identify the solvent, solute and solution from these.

Ans:

                    Brass is an alloy, it contains 70% copper and 30% zinc. The largest proportion is solvent, i.e. copper. The smaller proportion is solute, i.e. Zinc. The solution is Brass.

 

c. Sea water tastes salty due to the dissolved salt. The salinity (the proportion of salts in water) of some water bodies Lonar  lake – 7.9 %, Pacific Ocean 3.5 % , Mediterranean sea – 3.8 %, Dead sea – 33.7 %. Explain two characteristics of  mixtures from the above information.

Ans:

1)the constituents of a mixture (the proportion of salt in water) do not combine chemically.

2)Their constituents are present in any proportion by weight.

3)The constituents of a mixture can be separated by physical process.

 


4. Give two examples each


a. Liquid element

Ans:

  1. Mercury (Hg)
  2. Bromine(Br2)


b. Gaseous element

Ans:


1)  Hydrogen (H2)

2)  Oxygen(O2)

 

c. Solid element

Ans:

1)  Iron (Fe)

2)   Copper(Cu)

 

d. Homogeneous mixture

Ans:

  1. sea water
  2. blue virtriol dissolved in water


e. Colloid

Ans:

1)   Milk

2)   blood

 

f. Organic compound

Ans:

1)   Glucose

2)    urea

 

g. Complex compound

Ans:

1)  chlorophyll

2)   Haemoglobin

 

h. Inorganic compound

Ans:

1)   soda

2)    rust

 

i. Metalloid

Ans:

1)   silicon

2)    arsenic

 

j. Element with valency 1

Ans:

1)   Sodium (Na)

2)    Potassium (K)

 

k. Element with valency 2

Ans:

1)   Magnesium(mg)

2)   Calcium (Ca)

 

5. Write the names and symbols of the constituent elements and identify their valencies from the molecular formulae given below.

KCl, HBr, MgBr2, K2 O, NaH, CaCl2, CCl4, HI, H2S, Na2S, FeS, BaCl2

Ans:

 

Sr. No.

Molecular formula

Constituent element/ Name symbol

valancy

1.

KCl

Potassium (K) Chlorine (Cl)

1 1

2.

HBr

Hydrogen (H) Bromine (Br)

11

3.

MgBr2

Magnesium Bromine (Br)

21

4.

K2O

Potassium(K) Oxygen(O)

12

5.

NaH

Sodium (Na) Hydrogen (H)

11

6.

CaCl2

Calcium Chlorine(Cl)

21

7.

CCl4

Carbon(C) Chlorine(Cl)

41

8.

HI

Hydrogen(H) Iodine (I)

11

9.

H2S

Hydrogen(H) Sulphur (S)

12

10.

Na2S

Sodium (Na) Sulphur (S)

12

11.

FeS

Iron(Fe) Sulphur(S)

22

12.

BaCl2

Barium (Ba) Chlorine(Cl)

21

 

 

6. Chemical composition of some matter is given in the following table. Identify the main  type of matter from their.

Name of matter  Chemical composition Main type of matter

Sea water   H2O + NaCl + MgCl2 +…     Mixture

Distilled water     H2O Compound

Hydrogen gas filled in a ballon       H2    Element

The gas in LPG cylinder        C4H10 + C3H8  Mixture

Baking soda         NaHCO3    Compound

Pure gold   Au     Element

The gas in oxygen cylinder    O2     Element

Bronze        Cu + Sn      Mixture

Diamond    C       Element

Heated white powder of blue vitriol        CuSO4       Compound

Lime stone CaCO3        Compound

Dilute hydrochloric acid        HCl + H2O          mixture



8th science guide answer – 8th standard general science question answer – Class 8 general science question answer – General science question answer for 8th class


7. Write scientific reason.


a. Hydrogen is combustible, oxygen helps combustion, but water helps to extinguish fire.

Ans:

1. Water is a compound of hydrogen and oxygen .

2. In a compound , the constituents do not retain their individual properties .

Hence , hydrogen is combustible and oxygen helps combustion , but water is neither combustible nor supports combustion , it helps to extinguish fire .

 

b. Constituent substances of a colloid cannot  be separated by ordinary filtration.

Ans:

1. A colloidal solution is heterogeneous .

2.The diameters of colloidal particles are of the order of 10-5 m .

3.The particles of a colloid can easily pass through a filter paper as the pore size of a filter paper is big .

Hence , the constituents of a colloidal cannot be separated by filtration .

 

c. Lemon sherbat has sweet, sour and salty taste and it can be poured in a glass.

Ans:

1. Lemon sherbat is a mixture. It is made up of lemon juice, sugar, salt and water.

2.Formation of lemon sherbat does not involve any chemical reaction .

3.The constituents of sherbat retain their individual properties.

Hence , lemon sherbat is sweet , sour and salty to taste and it can be poured in a glass .

 

d. A solid matter has the properties of definite shape and volume.

Ans:

1. The forces among the constituent are called particles (atom/molecules) intermolecular forces .

2. In solids these forces are strong enough to keep the particles together in fixed positions, as a result solids have a definite shape and volume .



8. Deduce the molecular formulae of the compound obtained from the following pairs of elements by the cross multiplication method.


a. C (Valency 4) & Cl (Valency1)

Ans:

Step 1.: write the symbols of the constituent element

C                           Cl


Step 2: write the valency below the respective elements.

C                           Cl

4                           1

Step3: cross  multiply the valencies.

C×1                      Cl×4


The molecular formula: CCl4

 


b. N (Valency 3) & H (Valency 1)

Ans:

Step 1.: write the symbols of the constituent element.

N                          H

Step 2: write the valency below the respective elements.

N                          H

3                           1

Step3: cross  multiply the valencies.

N×1                      H×3

The molecular formula:  NH3

 

c. C (Valency 4) & O (Valency 2)

Ans:

Step 1.: write the symbols of the constituent element.

C                           O

Step 2: write the valency below the respective elements.

C                           O

4                           2

Step3: cross  multiply the valencies.

C×2                      O×4

The molecular formula: C2O4

Final molecular formula obtained by dividing by 2

The molecular formula : CO2



d. Ca (Valency 2) & O (Valency 2

Ans:

Step 1.: write the symbols of the constituent element.

Ca                         O

Step 2: write the valency below the respective elements.

Ca                         O

2                           2

Step3: cross  multiply the valencies.

Ca ×2                   O ×2

The molecular formula: Ca2O2

Divide the formula by suitable number ‘2’.

The molecular formula : CaO.


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